s^2-16s-36=0

Solution for s^2-16s-36=0 equation:

s^2-16s-36=0

a = 1; b = -16; c = -36;
Δ = b2-4ac
Δ = -162-4·1·(-36)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*1}=\frac{-4}{2}
=-2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*1}=\frac{36}{2}
=18
$